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* l F! b* Q2 ?& @ c$ @3 e1 j
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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
& w0 Z1 j$ @1 A3 U$ ~# p/ K
* g* r& S; _' e1 X( p+ X0 i 假设大路开这样的路:
6 v2 r1 {. C! Y+ X& G7 _0 K6 N. L' n1 o% @
12121212121212121212121212121212。6 X) h, n: L9 V- {; G
6 x! S5 Q0 ]3 D. J' N, T9 g4 V
按2珠路,就是BPBPBPBPBP。6 O+ X- U% `: T* C
) L. I1 ~" c7 k6 e 如果我们去掉第一口,就会出现完全相反的结果:% ^+ E0 Z" l }) d& P2 B
* \3 J, }2 U8 D4 P 21212121212121212121212121212121。! W; k' C# U( R( Y+ k4 I+ D
- n1 ?8 w# u9 E$ p
变成了PBPBPBPBPB。 j9 H5 v2 x# p9 `4 P
, T6 i4 G" X9 ~5 W- |2 j0 a
如果我们再去掉一口,又返回第一种情况了。) x, u, F3 s, V
* T }5 N; x$ x& e: ~* b 所以每一条大路,按2珠路排列,有2种不同的路数。4 g+ Z! O1 D. X
. ^+ k+ Z: A/ u) I+ r! i% F% _ 再举一个列子:. h# z) L! S! d2 \) b+ y9 Q5 z
. m3 D7 i$ X `+ c! ]; e1 r
大路:122122122122122122。- n9 C1 x( \% q/ H( K4 q
4 w0 M, a1 T3 m7 H. ~# J2 |
按三珠路排列:
1 n. O% Z2 j# }3 S3 o0 r( o U+ i' Q7 \! a$ }7 h
122,122,122,122,122,122。
4 F$ P7 U' ]. R7 @0 T \4 ^, A' f0 o6 y" Q' i: b
去掉第一口,变成:) {! ?% f: G i0 l5 `3 |! c
! {3 @% A, r; n' M: U
221,221,221,221,221,去掉前2口,变成:' G" ^5 Z# q8 X+ b9 ]1 `
; S( V" \+ Y: ^ 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
; v; c0 f R) K( I, O8 X9 L E
0 O# Q1 Q- t& p: f% B7 \, e; Y( L 同理:按N珠路排列,有N种不同的路数。
4 S( F, ?7 X4 q2 T. ?: }3 f5 l; @! H$ ?, U1 y. h; j! f9 m
我提出这个的意义在于:
3 \9 m" h" h F
# _) T6 P" s" u4 I# f4 N 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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# |# s2 k/ Q9 B8 C 2、为三多理论提供了下注的多面性奠定基础。" Z' F2 q/ w' ?, }
) `9 f% _7 v8 i& { 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。4 [1 f0 E4 \4 A
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3 l+ a/ a, r: [6 q6 B
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