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[lastpost] => 2767867 【YZ】9月22日投注流水3020元 1758606139 rainwang
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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。, R4 o8 k7 n c/ i! @1 i- F
1 f2 p" C8 U+ g/ I一般来说,
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二连赢的概率是25%
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/ p4 _3 s5 b2 Q( h7 s三连赢的概率是12.5%, ], e1 a5 n# ?: o* S! v3 s
$ a% p0 i) c+ v* J四连赢的概率是6.25%3 o8 F5 Q% K9 H- A$ W
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十连赢的概率是0.09765625%7 m+ \8 H2 D0 m* M6 y0 ~; a
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这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。8 t' f! Z( v+ M, S$ W2 \& M
1 Y( P* s2 E* B; b/ R4 {百家乐的真实概率含义是:
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假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球. ?, N! y3 |" W8 P% f* Y
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1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。
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. ^; X, J) T/ O ?你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。
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你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。
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# Z3 y: g4 b- I' D9 P* S另外一个说法是,
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8 V6 j6 y. A* b# M/ W1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。
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T# O* d5 }9 o2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。! g( y3 k; i# _! @; _) n, e4 J! L; X
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再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。: i; y1 ]9 t& R9 m9 S8 r
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平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。: E% P/ P0 Z( B- ?9 y6 r
" O9 G( o A' L7 k+ t+ X/ A对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。; m* S. P: q7 w& f- j
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举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。' h( N8 U+ M: w2 |- x: f/ C- f
6 U: w" r/ x4 S/ v第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化
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9 \/ m2 w9 [( ~+ z9 S# N第三,凯利公式的问题在于:形而上学。! R. @6 V2 g9 w: z Z$ ?
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首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。! n( L4 f/ q, W2 y `
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事实上,你玩的时候,基本上每次都能打到。& f3 J: `5 A& p1 l8 i
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因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。
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