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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
U$ Z' o5 g7 N% l% @6 c1 h0 y- l2 d: {& i7 {1 c0 f
发现了一个有趣的现象，
! `8 m1 i5 e& h9 }; W. I每一条大路，
4 L) Y x1 ], j0 m0 j. `按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f- b) T1 C8 h* k
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z" \- u: J' \& @
按4珠路排列，有4种不同的路数
1 h; e _1 ]( O! L/ [按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
3 J+ M( U. t7 {% ^' g& X- i什么意思呢，可能大家一时不清楚， K1 P J8 r- [
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
: V5 k% R7 T' y假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
- Q3 o4 u) `& u- J1 ^5 _12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h% d$ G8 v, n0 y
够极端了吧
; ^$ h* |2 f4 [$ _. F. C按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F$ y: n) F! z* [
如果我们去掉第一口，就会出现完全相反的结果：6 o1 T2 q4 v- h( c, }
21212121212121212121212121212121' i# O+ X- M/ W
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C. ?% a. ^( O. x* H% ^$ B7 E
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O1 N% x- v. D2 k# w& O2 j# a" @. }$ `
所以每一条大路，! R6 V# q$ h. c; z% O$ W) Q, h* X9 q; X" m8 [
按2珠路排列，有2种不同的路数。# e; G' Y# A/ ^- g Z& T" p
再举一个列子：; ^6 U3 K& s9 Q" A" g) ^
大路：122122122122122122。。。
% c. K; t2 a6 o4 P按三珠路排列：
3 U9 D# E5 d1 Q) [/ E122，122，122，122，122，122。。。7 j7 M! J+ Q9 N2 C+ m. m
去掉第一口，变成：6 G2 V! \" L' c" k: d$ A: k$ n" {/ s
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
4 ^& x) l+ @8 Q: w8 _# T去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W6 ?9 d" @1 f u; j! q
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `9 v% s3 b) I# I2 i& m+ w. H5 V
去掉3口，又返回122，122，122，了
) @! _, r/ v- z' X. |* b所以每一条大路，$ I' e/ A- D' n& v
按3珠路排列，有3种不同的路数。
3 [, r8 B8 P% A( \8 P同理：按N珠路排列，有N种不同的路数。
5 o% k. e. f: _9 O我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O! b- D3 z! Z) [/ |) A% s
字串83 L: R) G1 V- s2 Y+ Y
& [+ r- c/ c8 N- s* {- p, d3 [6 U. s5 J' [0 {1 A" m' k( @7 x4 n* S6 ]( e5 j, j- x: V5 L
1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |% _ [2 x# g. e( u, @0 X
2、为三多理论提供了下注的多面性奠定基础。
2 q. I: Y9 \1 c3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.( j: Y9 @/ Y+ d' a3 E* o# V. {
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