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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
, w/ B- d2 f- ^
" U. Y! I% m( X$ ]& M发现了一个有趣的现象，2 z8 G/ V) C6 f$ Q5 Y8 k+ G7 h
每一条大路，
9 w$ M+ ^$ O2 D) |8 a' o按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f( N2 [& J& C! f
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z+ t! A x) C Z" @8 K
按4珠路排列，有4种不同的路数
& V9 C/ V- i& A6 e2 Y# n0 e- i按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C. c2 ]: c9 ?. n3 u W
什么意思呢，可能大家一时不清楚，5 M: Q- L8 \( `
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l( M I7 ?/ e( U4 d! S* ~1 D: N
假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
v5 n$ S6 a" M' w |3 L12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h( S$ i+ a/ `* w1 |, c
够极端了吧
S# o/ o) w; Y按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F4 m; H2 h, q$ A) f( i. F
如果我们去掉第一口，就会出现完全相反的结果：1 {( r" |$ W+ m" g- d
21212121212121212121212121212121/ F: ]! u W0 H g+ o: E
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C' y. E+ i5 U9 Z# v+ S2 g9 F
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O1 I/ s3 Y1 b& I) k; a
所以每一条大路，! R6 V# q$ h. c; z% O& M. |4 F8 m+ @8 e' L9 [
按2珠路排列，有2种不同的路数。6 t7 m2 h% b: L7 j! Q
再举一个列子：& v1 ~7 U' U5 u
大路：122122122122122122。。。7 P# C2 n0 u6 {. u) q
按三珠路排列：
( p4 y: V7 u! K: S122，122，122，122，122，122。。。* N! z9 M- W+ {& K; r
去掉第一口，变成：6 G2 V! \" L' c" k: d
: }# x% ^, p, Z" z, b) d221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M" R( h# x4 k/ \; ]/ q6 V" h6 I
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W& Z" b2 g: S2 `0 l i
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `7 k# ]" `1 _$ a
去掉3口，又返回122，122，122，了# W' u! R H( I8 x6 d; P) M8 y
所以每一条大路，
6 M* M& p$ H! E" \# b* E按3珠路排列，有3种不同的路数。
, m# w) Y8 D) v4 w同理：按N珠路排列，有N种不同的路数。
# f- k# A1 K! Y+ Y我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
6 E$ X+ |* J& X1 \8 _3 ]: |2 F( x2 H字串83 L: R) G1 V- s2 Y+ Y
8 I) D- R0 X. b8 Z2 u$ q- p, d3 [6 U. s5 J' [0 {1 A" m' k( @. {$ ]& |, G: V: G6 f; q
1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
9 J' B4 |9 u9 R/ g) M/ U2、为三多理论提供了下注的多面性奠定基础。
- x+ b! ^& ]9 _/ T3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
- i$ T' g* y: r& ]3 b4 a( o5 V( m |
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