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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O' c1 b# t: ~! @; E: _9 Z
* f" K/ V' X: W9 \
发现了一个有趣的现象，
4 L, C. z+ g5 V& l每一条大路，
$ \- E* P0 U: X; z. {* B4 r) l按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f+ K+ H9 s$ @* i' p$ Z, E
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
9 `6 [ F' h v: L) |' ~. m& D4 b按4珠路排列，有4种不同的路数/ c# f v' F8 a2 o* z4 e
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
- h1 t* y N+ H; g6 Q什么意思呢，可能大家一时不清楚，
7 D8 _: I' o, S我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l7 M3 d: w( w3 ^; J# `
假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
! h G" o2 J0 G3 i) i0 T12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h$ J; S1 T6 f0 d+ k+ j" z" x
够极端了吧
# y l9 v3 \0 g) p1 a按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
* g/ o3 w9 {" v如果我们去掉第一口，就会出现完全相反的结果：6 R$ h3 l3 Q6 n, A
21212121212121212121212121212121
5 X: H3 Z& C; ?变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
4 q' C2 M& d8 X- i8 Y: D2 N如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
; Z6 ^3 T% O: A* N l* b所以每一条大路，! R6 V# q$ h. c; z% O
1 X u% z, A6 B* p# m0 {/ c4 U按2珠路排列，有2种不同的路数。
8 l3 c4 M U2 D8 Y% A& t再举一个列子：% S6 l, v! F {+ L/ r! h4 A8 `
大路：122122122122122122。。。
, K& }; G1 J% M按三珠路排列：8 F k% Y) L6 G. t, n
122，122，122，122，122，122。。。
1 v4 \* b, b2 R去掉第一口，变成：6 G2 V! \" L' c" k: d
Q* J! {% r6 {9 v1 N221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
, N: @4 p# g3 z h* r" d% Q% I去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W% a, y6 `. c; W: e( ]2 W$ q
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `
" g, ?' C4 v! A. o2 C0 j去掉3口，又返回122，122，122，了
0 b' X! r& `' h9 e( C# Z7 L, W所以每一条大路，! H9 r4 q2 E6 S1 M" G! `4 y6 d9 U1 C
按3珠路排列，有3种不同的路数。
+ v( y$ S+ U9 v9 }# {* j同理：按N珠路排列，有N种不同的路数。
0 r! [" n8 J* L! ]3 ~我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O7 Z1 }8 R+ @3 ?: X! g& Y3 q
字串83 L: R) G1 V- s2 Y+ Y! L0 V; l5 a4 U+ i [' c. c6 k% p
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @; [5 |1 q1 I2 w) f* r& D9 h( V
1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |( ?; F$ u- M. \" {
2、为三多理论提供了下注的多面性奠定基础。- x. h0 Z# c; m( S, M) e# c
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
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