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眼里没有庄闲，只有连和跳，因为庄闲是一对一的，而连跳都是一对二的。理解也好不理解也好，这个讲起来费劲，就不过多讲解了，你只要记住百家le只有连跳没有庄闲就可以了，通常大家所看见的大路，第一行是满的，从第二行开始才有洞出现。% T4 v; N5 u" d4 z/ q2 d- \/ \
2 f; |0 R, q# k* J9 i+ E
用什么办法把第二行也变满，让洞出现到第三行去呢？这就需要重新排列大路。一种全新的方式去排列大路（又是新用什么排列，用连，和，跳连就可以比如大路是(随机的）
! f. K k0 }# p! |6 U
8 m0 J" A2 x W) a l, p 第一行：OXOXOXOXOXOXOXOXOXOXOXOXOX（第一行永远是单跳）
" B2 C+ |6 Z2 ?5 J: `5 E: {
: u" n# M$ w, t3 K( I; p0 t 第二行：O X X O O OX O X （第二行开始出现洞）5 K6 `8 L4 {4 O( v$ `" m6 a
# x5 v8 V6 R3 K* A 第三行：O X O X X
# i# J; q& i% X
9 ?& D0 o c8 z6 `( p+ w6 j" s7 y 第四行：O X X
4 R! y& e; q6 X/ s( c- k; R, W' y7 M }/ \2 q: H! @ L- u" Y
第五行： X
4 i3 R) Q7 w/ b. t4 h
% X/ x+ p/ ~4 D1 ]+ \ 那么新写出来的大路是怎么样的呢？6 R9 f" T+ N8 f; Z) ]7 e2 f
) Q8 ~; S/ c; z% ]# @4 K# n# [
记住一个简单的口诀就可以写出新的大路：1．连是连；2．跳连也是连。
+ K7 p7 U$ y: G9 `% k0 E3 a8 x& M" Y* W
如下（大家凑合着看吧，实在不行就自己拿笔抄一遍，和上面的路一一对应。）% c& ? _9 D' Z7 p* O$ T
# ]; ]# Y( v! `9 b
第一行：OXXOXOXO OXOOX（第一行不再是单跳了）* Q. I7 j4 X; \5 s
0 x/ F+ L) | W: [ L) d4 l 第二行：OOXXXOOX XXXXX （第二行也是全满的）/ ]6 ^9 U: d" i* z
$ A% E# F3 s" U2 E
第三行：OX OX XO XOOX （第三行才出现洞）* q0 r: S: d; u7 H- i
. G+ C6 g0 ?' L' Q9 p, ]+ b* V 第四行：O XO O XXX / i. r* y" O& O! J* S( ^/ I4 y
7 ?2 ^# x6 [. }7 m% w0 t. f6 U7 o 第五行： O
* f' M# o5 `2 x# D' \
( V, E) c$ n8 D* N& t, | 通过以上排列，大家看见了，变换了组合方式以后，大路不再显的那么杂乱无章了。每一列要么是连，要么就是跳连。这就似乎是最初期的关系形态变化组合排列，通过这样的排列，从形态上看，整个路只有12个形态上的跳，其他全是连贯的（可能已经有人开窍了）。1 h ^# h5 x$ V8 Z4 t1 M! E# B1 d. {5 J
7 N- V8 X' }' s6 m8 @' |. Z
大家看第一行不再是完全的单跳，第二行没有洞的出现，第三行才开始出现洞，每一列最少是2个符号，通过这样的形态组合，实际上是减少了原本大路上的跳40%-60%，比如原来一靴牌60把，基本上是30个跳。30个左右连，而且是间隔无规律，杂乱无章的，按常规跳连的次数是基本一致的，周期越大，数字越接近。% W0 `4 A* \' T' Z: V0 V
% e. t7 q* @! m+ q: _: L \6 n( n
通过配列 可以把原本大路的跳精简到10-15个左右，相反增加了40-60%的连，以上是对大路形态转换的最初级形态，相信已经能对大家有帮助。至于怎么样去下单 ，一目了然了。; u7 v7 x) q8 o% m8 ?, ~ ?
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