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+ K' u: K& S% g* Z' y0 L
* X9 n9 A/ V. a" A: j& h0 `通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。2 x+ o6 S; `: e) t5 R
9 }; i( B$ m; L9 p- z: ^
假设大路开这样的路:
" W1 d y$ |. Y2 Z$ [( i" [* s5 D- _; h9 N- q, M
12121212121212121212121212121212。 A4 O4 ^: t& Y4 R _" \7 g
) z$ M' w' c- q3 { W* Z 按2珠路,就是BPBPBPBPBP。2 ]) \1 X$ A0 @8 f
' t' L& _) q- n z- R
如果我们去掉第一口,就会出现完全相反的结果:
, M2 h ?$ b: w# n9 D- u$ m" y7 I) L
& C. d' i _7 y0 _& D e 21212121212121212121212121212121。
5 ]$ _. D7 d. j; ~1 H* B( n
! H5 N3 U5 ~! m" T' k/ V4 x1 \# z 变成了PBPBPBPBPB。
% @+ L$ L' I/ o4 h g% K4 `! \/ y O6 b* w
如果我们再去掉一口,又返回第一种情况了。
8 ]2 a" ^+ L9 v! Z0 V. W3 M7 a2 T1 g g
所以每一条大路,按2珠路排列,有2种不同的路数。1 M' |* [) ^6 |+ U. P* k5 s
7 h1 `: W4 U# [7 ~' v 再举一个列子: h$ f9 _! d5 o' m U
! q' `) E4 Z# ^' z
大路:122122122122122122。9 n9 }2 Q( z3 L3 g* I8 r
" o% p' w! x4 u3 Y" M, X/ }
按三珠路排列:
, O* @0 S |; P0 I1 ~& j. _
7 s0 k- S6 I- a# J: C 122,122,122,122,122,122。# q" f6 z' _4 B4 P9 g7 d" x
" d. j7 w6 l4 ^6 e+ @ 去掉第一口,变成:
* H/ ?4 [1 i) v, E6 E( ?+ W
. y) y( i/ L2 S8 I% x 221,221,221,221,221,去掉前2口,变成:0 k6 J. ^" [1 m" a
( k- i4 w+ T V% M/ g 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
% K- h4 r7 N1 J5 H# W% E9 l$ X5 a3 m" S
同理:按N珠路排列,有N种不同的路数。, S2 p$ }: L) _4 F
" R& `* n* q* d+ o9 z% D0 n
我提出这个的意义在于:3 P3 e6 T6 T$ M) I6 Y7 G
, L8 }$ }+ M, ~4 B$ S
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。/ o! Q+ G* x: E1 B
# \7 O$ R7 m/ F 2、为三多理论提供了下注的多面性奠定基础。
3 E/ B- {: h. d. E: ~3 u
8 u; H2 G, h+ F 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。6 F* ?- [: i5 Y( M' U9 M# r
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