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通过我几个月来对珠路理论的研究,5 R+ y* d$ ? k6 I7 G/ O
5 O* j/ q O$ {: ^% p
, X. L! f/ Q" B3 o; w2 c2 N' ^发现了一个有趣的现象,% N$ b6 Y% S. p. y- E
每一条大路,1 O! R- \! q7 ?# x
按2珠路排列,有2种不同的路数1 _% l2 j Y8 @" u) {# f }: J4 W, e/ y" |2 P
按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z+ K% b6 y/ l U
按4珠路排列,有4种不同的路数2 V1 Q( y" c( v) c+ p( J
按N珠路排列,有N种不同的路数。: n1 f3 R9 @ p% ]* C# O/ s: Y8 A2 x/ z, ?: Q3 c5 y- X8 y
什么意思呢,可能大家一时不清楚,. p$ G( h9 B% b, I5 I* k! \
我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l- B& ?. d* n% p7 `/ \
假设大路开这样的路:! z ~0 G3 v. K' o5 A4 ]" }5 w# u3 ~& |5 @( S" Y- y: K& Z1 u1 |
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
8 }) `/ L9 I% C' v/ M: P够极端了吧/ i1 j# j# x; ~& N, o' O1 `. {
按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
, T+ M0 X. G/ @5 Q; `如果我们去掉第一口,就会出现完全相反的结果:, q2 o1 {% B) j! f. `
21212121212121212121212121212121 d! U9 m4 ?+ L& e1 J2 N7 P6 B# M
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
% N2 Z, o0 a6 w: e( }如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O) b; O4 L# X6 L( m( _2 o
所以每一条大路,! R6 V# q$ h. c; z% O
' V/ _) U8 p' }, Y按2珠路排列,有2种不同的路数。
9 o9 O* K7 B0 n& N4 V) [2 V7 e4 E再举一个列子:5 a4 }2 J' v- s
大路:122122122122122122。。。. W1 M1 }# ~' a& t, S: U% s
按三珠路排列:
' |; s- L" h. d* L. o# e6 W/ i122,122,122,122,122,122。。。$ I; L# x- |' p
去掉第一口,变成:6 G2 V! \" L' c" k: d! j1 Y* k) U6 _
221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M1 i8 @7 B, [$ E% J3 ]( H
去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W q5 X3 h, O7 u7 a6 o
212,212,212,212,212,: y& l, B; I6 e- m. J# c) `
0 M; W6 _1 o& S& m1 G$ H去掉3口,又返回122,122,122,了0 z7 X" i1 w& f) M
所以每一条大路,
4 d: i w* A" o1 B) F8 }2 j按3珠路排列,有3种不同的路数。
9 o( b( Z$ P9 O' F! C- y同理:按N珠路排列,有N种不同的路数。" u3 R4 {" I( P: z. k
我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O
! c1 L/ Y* G2 e) H; M$ I' v& L字串83 L: R) G1 V- s2 Y+ Y" l* j3 H, E; s; z& ]. _
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
6 y) B, o, E/ w1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |) y, x/ y* I( g$ c- `. Z
2、为三多理论提供了下注的多面性奠定基础。) k5 c; s: F9 b
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.8 r& F2 m0 H6 V$ S
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