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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
( J7 R; U Z; E4 w4 M5 [, O0 N6 w
+ {6 G, E; L0 r发现了一个有趣的现象，3 v: q7 N) g* F
每一条大路，: x3 O* M/ ?5 y# b0 U; s
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
8 J, g. A$ {/ Z. V按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z) Z: F B& S+ x7 u! q' _0 Q) ~
按4珠路排列，有4种不同的路数5 B1 A: u. w$ b7 N3 {4 l
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
2 R# Y6 z* ?1 C什么意思呢，可能大家一时不清楚，+ ^( A; F% z) k6 @/ L, M
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l- L c$ l# [( ]; B
假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u' @/ T O5 ~1 d) \
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h. [' F/ h9 |' R* ]# Q
够极端了吧" n! y2 i" w, G1 N
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F6 q! \* P0 G; L: c) u+ h
如果我们去掉第一口，就会出现完全相反的结果：+ w3 H4 ]; R8 X; k- r
21212121212121212121212121212121) h7 V7 D0 ^, @7 j
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C f2 v5 I# c9 X0 R+ p
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O1 k7 ?% w7 i1 I. J z" g0 I% y
所以每一条大路，! R6 V# q$ h. c; z% O
" V" {( ] Q; w/ C+ H% E5 }按2珠路排列，有2种不同的路数。
+ ?, ?2 K3 k: G# g再举一个列子：
* D, u5 ^& e/ M' x6 V大路：122122122122122122。。。
- D$ f8 P0 H5 f按三珠路排列：
0 |: S7 {" n( {+ Q$ `0 p122，122，122，122，122，122。。。9 i/ Q7 l5 _+ q) U
去掉第一口，变成：6 G2 V! \" L' c" k: d
P) d; K( ]5 F; H$ R7 F+ N221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M8 ^, T, c! n6 N( K1 p9 s& _
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W* P0 @" Q6 W" |8 b1 I
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `; n: f0 G5 [' f; k" A% m
去掉3口，又返回122，122，122，了
( r$ \1 T% I/ q4 K. w% o% d所以每一条大路，
s" i# Z* A4 O3 u M按3珠路排列，有3种不同的路数。' O" c) z- M5 E& r% S, }
同理：按N珠路排列，有N种不同的路数。, g9 M. Q i, L. T `% P
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O0 U9 N) j9 U; A
字串83 L: R) G1 V- s2 Y+ Y
% `/ q; r. q$ z% c; z; `4 I- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
. z, B. C. z1 y6 z; [4 x+ g1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |) `2 l8 v# S$ C# B
2、为三多理论提供了下注的多面性奠定基础。
3 b6 G* X/ d4 {0 U8 c2 y3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.3 {; C x5 Z/ b3 S1 g
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