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[打法交流]
百家樂終極破解-理論編:不斷更新 [申請精華]
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本帖最后由 wlcomp 于 2011-10-16 08:28 编辑
1 K5 u+ E9 K6 x* s# |6 e$ h0 J _* J0 p2 u; [8 k+ s
第一章
9 S: x$ O3 F, D: E/ X引言:
; R) D( s% ]3 I+ t5 t# Z% M9 L十五年前,剛在DC 工作不久,百家樂就引進我工作的DC ,幾年後自己也開始玩, 當時反問自己, 為什麼一個比大小的遊戲, 要弄得這麼複雜,因些開始研究它的原理.百家樂是一個將正常數學系統不斷轉變的遊戲,因此當兩三莊之後,如果出現系統轉變,本來系統的閒牌會轉變成莊牌,長莊就因此出現了!根據野史,百家樂是兩位數學家為了爭論可不可能有違反統計學的系統,其中一位發明了百家樂,所以百家樂中,每一局的莊閒比例大多數不是50/50.
/ f1 [+ H# W( V" p, ^: S7 ~& ]- J1 w2 R l
百家樂的變化:
7 Y/ `2 J; _" A1 _- k, q) {0 M首先要明白百家樂定勝是分別有三種形式
$ I% a# Y$ B* w, ~ ~/ f( S2 U. u1.四張牌定勝-下一手,莊閒不會轉變" Q" _; R) D2 @
2.五張牌定勝-下一手,原本莊的牌會走到閒那一方,原本閒的牌會走到莊那一方.# }) r3 y9 k8 I' C
3.六張牌定勝-下一手,莊閒不會轉變,但在統計數上來看只是統計多兩張牌.) {1 ^7 q; Y9 S7 B
' m+ Q) C* C6 N! c: ~& C0 ^
破解原理:
$ W1 m6 m( n) e1.首先要明白,一局牌洗好之後就不會改變
3 U9 D+ U: g7 Y0 {/ ]% W2.要知道發牌方式,第一 三張是給閒,第二 四張給莊. g( R Q- h- a4 G2 ?( S& U3 J2 C
3.如果把一局牌分兩部,第一部分單數列-第1,3,5,7...張牌,第二部分雙數列-第2,4,6,8...張牌9 t: ]1 u g9 i7 D' |, B6 P6 r, ~
4.在一開始,單數列的牌發給閒,而雙數列的牌發給莊
7 d* V! _! U* a9 y" c. S- b0 t5.當五張牌定勝之後, 單數列的牌發給莊, 而雙數列的牌發給閒& o; Z0 ^' c0 X, P! J: a5 M, A
6.四和六張定勝,發牌方式不有變化% y5 {. p' F8 o4 N, F
7.當五張出現之後, 發牌方式會再改變一次
y, A5 Z8 S/ p9 |% C# s8 t8 d3 l8.因此去分析單數列及雙數列牌的分佈,就能精確地估計出結果. D# h5 m& V1 A, I2 k0 ]
8 D( X) J$ w& c' h( N! |
6 m/ g' Y8 k( C t4 F! E' f3 y. N以後章節會教大家如何分析出精確的結果 |
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终极破解，不可思议。。。。。。。。。。。。。。。。。 |
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