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# [5 q3 h1 x, g0 i; m. A, y% t( V
$ G: I8 n( x* l. ]( Q/ M通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
1 L9 O- g' F. B& i" @) S; y2 D3 G( f
假设大路开这样的路:
, L- G ?9 l0 \( |
2 z* v/ {3 M8 C2 o 12121212121212121212121212121212。
# Y1 J" {, M( m4 t9 n
+ E+ Z# z6 M ^: N7 f# c 按2珠路,就是BPBPBPBPBP。
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如果我们去掉第一口,就会出现完全相反的结果:- Z( T6 ]7 m: [2 `
" v9 N8 ^- l3 q' v/ [ 21212121212121212121212121212121。
* G/ o8 w) G/ J) z! G0 L* b
, J8 t0 X0 q# e/ ? 变成了PBPBPBPBPB。
% d F/ R: Y& d8 g, n0 E* b; O5 Y& [+ `+ Q( a* E! `$ W- t
如果我们再去掉一口,又返回第一种情况了。3 \# ~4 ?, R1 V3 m- b0 [+ [/ r
- ]; l8 z. y l' B' h+ e# y 所以每一条大路,按2珠路排列,有2种不同的路数。
: ?; z5 }2 V/ k
. B7 d! `( U" W9 ` 再举一个列子:
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) h+ X* L: F# Q A: P. |, E" } M% @ 大路:122122122122122122。
" g/ h( f% B& e, p9 b0 j" I. @* l7 n
按三珠路排列:
- ` ^& A- L% J" V8 E+ U/ G3 Q- j7 g, o7 g
122,122,122,122,122,122。; @$ Q' {/ U* c7 D' x @
3 I; l9 c6 x% x, s0 S4 z' f& E 去掉第一口,变成:+ R3 ?& _0 S: ^: `0 k/ q
/ b/ n1 u- x l& Z( c" s. ` 221,221,221,221,221,去掉前2口,变成:, P: i: ^* K, h; `- I
6 u2 E; K) i. N
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。2 V* z$ d' c7 `5 J; N7 O
7 W$ T& J2 [2 z" ?# P( j2 J 同理:按N珠路排列,有N种不同的路数。
K; o* Y' |8 \$ U) f
* P* I9 M6 _! M5 ]1 P. F 我提出这个的意义在于:; x7 }# l8 [! @" j3 g6 {. v
/ w2 C' o: n3 s: F; L( J: Q 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
* Q4 V* @- ~% Z$ x" b0 O& x- y5 T. ?+ h5 A1 a& l
2、为三多理论提供了下注的多面性奠定基础。2 t$ b1 p& x* o+ B
' W* K8 p# t, o. P0 |% [ 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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