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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
5 S' W8 R2 b0 ^5 N7 a7 B! g' v5 J5 s: r3 z
发现了一个有趣的现象，
8 q2 c3 X, k2 }8 i0 q每一条大路，+ e9 }# S7 o2 m% U
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
6 B, B3 B* \+ {6 \# ?$ }按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
- G& g+ {& A0 M% j8 N8 I按4珠路排列，有4种不同的路数' n3 V5 Y4 R I% l7 v
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C G& e, {+ v& a# g, H! m! Q
什么意思呢，可能大家一时不清楚，6 o- h! o# j& V& n
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
7 g, B6 S1 c3 n& l- V B8 z8 J假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
' ~7 s7 K* k8 ~( a$ O" r# a0 q" b12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
) d4 K( u- J3 R$ S, r3 d够极端了吧
) ^+ E- h( O# p! D" V! p按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F/ n- s3 d9 F2 _; b% j
如果我们去掉第一口，就会出现完全相反的结果：
0 E) \3 [8 m: @: n4 l21212121212121212121212121212121
- T* E( N1 ?$ o \变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C7 Y' P# x- L: {5 Y
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O% C f6 U% `$ d0 [
所以每一条大路，! R6 V# q$ h. c; z% O% y' U/ i" i+ Y# N2 Q7 `
按2珠路排列，有2种不同的路数。
/ s+ {. h+ m5 T* {再举一个列子：
! a# p( U* T& O( W- \# ^( _# N大路：122122122122122122。。。' U8 C& J, P. f1 T' @2 ~- z/ e
按三珠路排列：
7 g y* x6 H! \% e& z; s( I122，122，122，122，122，122。。。" \! g# y# n; G) U+ q7 }
去掉第一口，变成：6 G2 V! \" L' c" k: d9 `1 j% {0 L% t& E
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
% s0 F2 z& N" Z, b$ i l y去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W
3 Z$ C, f# D9 p! q/ F7 Y, {3 I/ ]212，212，212，212，212，: y& l, B; I6 e- m. J# c) ` i, d# d0 X6 `5 I
去掉3口，又返回122，122，122，了; _0 p8 j- D" S( j7 y
所以每一条大路，7 |, l+ ~8 ~$ b& T: N$ E0 G' N
按3珠路排列，有3种不同的路数。
; [" P/ E+ a& u) z. {同理：按N珠路排列，有N种不同的路数。
/ a/ E! O; f$ q F$ _" X+ @我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
. x; [6 G L5 Z字串83 L: R) G1 V- s2 Y+ Y
* I9 Y. J; e! e. U8 z% K7 o- p, d3 [6 U. s5 J' [0 {1 A" m' k( @( b: q0 F7 x3 @$ H, J6 h
1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |* r3 b/ Y7 S* G+ m w
2、为三多理论提供了下注的多面性奠定基础。$ n) d+ g' w4 m" V- n; V
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.3 c0 w; W! {* T6 w7 P
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