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[打法交流]
近期在网上研究到了个百家乐著名战术 蒙特卡洛战术
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百家乐蒙特卡洛战术,需要纸和笔。但是不很难。* d* U3 K5 r% k" o5 G
4 A! E3 z6 ~( N(1) 首先写「 1 2 3 」的数列。0 Q) y/ i2 F/ I3 V" @# f1 f# i1 u4 d
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(2) 赌本就是左端的数字 (1) 加右端的数字 (3) 即是 (4) 。1 O H- q1 G- |
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(3) 输了的话就在数列右端之外又加上顺序的下一个数,现在这个例子要加的数字 (=4) ->( 「 1 2 34 」 ) 。如此类推,并且重複上面的第 (2) 点 ( 但今次会是 (1)+(4)=5) 。
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1 @' B! w, H: Z {(4) 胜了的话,倍率 2 倍的游戏就把左端的数字 (1) 和右端的数字 (3) 消去。倍率 3 倍的游戏从数列上去掉左端的二个数字和右端的二个数字。5 ~: l3 A7 H6 _8 Q, {% Y
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(5) 如果数列所有的数字都消了就代表结束。1 @! ?7 a( p( S3 |3 p
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(6) 想继续的话,回到 (1) 。- y. h) h: D9 V1 _8 J" Y
, }" I% b" y# k蒙特卡洛战术的问题,在于如果没有充分而源源不绝的赌金,就会出现途中被迫停止的可能。而且连败的话,亦有机会超越 Max Bet ( 赌注的上限额 ) 。" m# d( c3 o. @
]$ N( t( I& b; B; G% G二合一战术6 P- o! l8 f9 L! I
: X) F8 L3 R! {: J0 _这个可说是蒙特卡洛战术的一种,是以 1 局取回 2 局所输的方法。方法简单。写下输了的金额,赌注就那个左端和右端的数字的共计金额。
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; L% n, j$ [2 ~; C) W/ i7 ?譬如,先写下「 1 」。所以第一局的赌注是 1 。如这局输了,右侧添写 1 ,成为「 1 1 」。那个下一局赌注将会是左端和右端的共和 =2 。
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3 T* u' u+ e" ?$ x$ f1 d反复这样做,如四连败,数列将成为「 1 1 2 3 」。因此下一赌注会是 4 ,而且胜了的话,消去左端和右端的数字,数列将成「 1 2 」,下一赌注就等于 1 和 2 的总数 3 。再胜的话,会变成?. E9 j; t! ?8 [
; M8 ^' e: r/ u4 U1 r9 O: h儘管结果是 2 胜 4 败,共计收支是一加一减等于零。
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+ ^$ J/ ~$ X* R( o这方法我试了不咋地,你们可能可以?, B/ q5 {# C" s" I( n% C2 J$ F+ q
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