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[lastpost] => 2796704 【星宝】1月13日投注流水30000元 1768309582 22301
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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。
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/ R5 y- V7 T* A! j一般来说,8 _, x' h* v* S- b; W( } X4 Q; E
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二连赢的概率是25%; j* g" x* H3 p* |
( I2 m2 ?; T3 K% Q三连赢的概率是12.5%
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( T9 `; t8 Y% g+ @' P四连赢的概率是6.25%2 k5 F, K4 X* N' M V7 t1 \$ q: L
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……
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十连赢的概率是0.09765625%' a9 g8 ^: l7 g, ~# z: ^& p7 {, e6 k
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这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。4 Z( q$ Z) P7 d; W! p
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百家乐的真实概率含义是:
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: c6 V' j: ?6 v4 L: [' t7 x假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球
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, t: L5 c" u* y2 m- q6 k% `% Q1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。2 k% @: e, g+ r/ F
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你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。7 W; J8 t- i& r- b
9 G4 n. d. ~- a% U$ w5 ~5 r你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。( ?$ F; h( v; d( Z% B7 j
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另外一个说法是,% L- X- B# j! s5 n1 J. f& Z- _! p
v3 v) C+ \* T0 {* b) |1 N3 D* `3 S1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。+ v4 f/ S7 o4 v% N g" c" a7 I2 l$ X
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2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。( b/ w$ B1 t# a& Q# L
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再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。
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. v( B4 i$ v2 C. @7 `; R+ y平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。* P4 w- c6 I0 I/ e) R( r
9 F8 v7 j! t6 H7 ~/ m- }" {% z对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。& p' f x* r) L
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举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。
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7 ]" i, q7 T1 }- ~- o& e0 F' z$ k第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化
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/ }. e& M. g/ I& D第三,凯利公式的问题在于:形而上学。
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首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。9 R( S# D2 s) ?* S
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事实上,你玩的时候,基本上每次都能打到。( k7 E8 T$ D3 N
" t5 O5 \- Z' o# i1 h' {2 ], J# I因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。: R% f2 \6 q# n( F, B
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