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5 ?* k4 Y9 a( W7 w/ z9 I通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。* C* F8 N2 U2 C* t: \
9 X; m. Y7 M) s8 N" m) E 假设大路开这样的路:
& R% c' F |: b4 _# I- v
4 P, J( l# e3 l2 ~0 O3 L 12121212121212121212121212121212。/ w' b% O2 [) k1 K
1 ^3 C! y; h' `: l( G
按2珠路,就是BPBPBPBPBP。
, W* a% G5 p6 o% R% o2 A8 Y8 E# u& a# N$ Q6 l1 h6 d! {/ b( N
如果我们去掉第一口,就会出现完全相反的结果:8 j- q$ h9 H8 F5 Q1 Y9 Z
' W( J, U& F7 _( m# n9 Z) Q* f 21212121212121212121212121212121。2 ^/ h2 x5 x: l# W1 A- d
; t n: H- }, u
变成了PBPBPBPBPB。
6 K! r1 T+ C: z: ~. c. H! C& e5 s
如果我们再去掉一口,又返回第一种情况了。/ c# c) O% K0 y5 Z9 c" `" ~) R+ c
2 B) c* `+ m H+ ^5 T7 [$ m) } 所以每一条大路,按2珠路排列,有2种不同的路数。
5 A# M+ c: K% y0 t
0 e0 @" y8 W, T7 L; x! l 再举一个列子:6 ~: u5 n) _. k- Z- u6 ?
$ m8 e+ R+ x, _9 T, |
大路:122122122122122122。
2 G' e, @! r, M$ X4 g- I# R- v N9 o! O2 g6 i+ i3 p8 Y: p! \. K$ _" m# [
按三珠路排列:
# O9 N# S3 g& q
1 i7 d2 N' {7 C$ X- Z 122,122,122,122,122,122。
. ^2 R* X, L2 x; w" I$ ?7 _
& M" W1 [$ @( N L" U* n 去掉第一口,变成:* r6 X& B1 A$ G4 {( {& ^/ V
+ P2 I' L: `& {- a 221,221,221,221,221,去掉前2口,变成:
9 H$ {9 Z7 |- b6 Z
" i [1 o x% c* l8 f5 o 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
! I! b2 Z& Q' M) N1 a
/ q4 }4 u E& T# \$ T 同理:按N珠路排列,有N种不同的路数。+ p+ h' o: g! c7 B
0 J9 Z5 X! c% F. d5 S9 ] 我提出这个的意义在于:/ {5 O0 ~! R; G% x
d: N9 }; D6 A2 u* d' N* ]
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。1 W% m! X3 x- W& g( r, q# G
% I4 l/ W! t* u- K 2、为三多理论提供了下注的多面性奠定基础。7 N! ]3 G0 h( i1 b5 a+ \8 p" x
8 X! J4 j) x1 ?& T 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
4 Q" y0 y$ o8 O7 D- r7 o' A+ [
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