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眼里没有庄闲，只有连和跳，因为庄闲是一对一的，而连跳都是一对二的。理解也好不理解也好，这个讲起来费劲，就不过多讲解了，你只要记住百家le只有连跳没有庄闲就可以了，通常大家所看见的大路，第一行是满的，从第二行开始才有洞出现。* h% O5 }9 @7 N2 C! s
8 c" M! B" l/ Q# v; E 用什么办法把第二行也变满，让洞出现到第三行去呢？这就需要重新排列大路。一种全新的方式去排列大路（又是新用什么排列，用连，和，跳连就可以比如大路是(随机的） n5 _8 r, ^- `7 f& j, `
! G$ |8 C. O. P R2 l- } 第一行：OXOXOXOXOXOXOXOXOXOXOXOXOX（第一行永远是单跳）
* v3 q5 `) O2 L) z/ {% k5 X4 N! `9 A0 [, J3 l C6 J
第二行：O X X O O OX O X （第二行开始出现洞）* y0 j4 {1 J& y! P* ?4 i- G- E& D" }
" B5 `- f4 x7 J6 h$ u
第三行：O X O X X" I6 k1 b, o, \8 S4 D7 \
5 `3 }* q) f* | 第四行：O X X2 }: e4 \. @: U. ~& L; {/ \
9 i$ e6 q7 X/ V
第五行： X
3 X- g% p* j# J- q' X, k, t \$ ?& B5 k/ h3 J- _# ~' U1 V y
那么新写出来的大路是怎么样的呢？
/ F6 C6 K9 ], A- g3 w- S9 L. G( P' m! l0 g, @3 l# d
记住一个简单的口诀就可以写出新的大路：1．连是连；2．跳连也是连。6 n$ w% J" M" X5 H
/ F! m, v* c5 b! G/ t 如下（大家凑合着看吧，实在不行就自己拿笔抄一遍，和上面的路一一对应。）
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: I3 ^7 m* {$ ]4 n6 l8 T& Q* q 第一行：OXXOXOXO OXOOX（第一行不再是单跳了）2 k+ k+ E0 g: I" G
! }/ n& E# M: T* N0 P' Y( ^ 第二行：OOXXXOOX XXXXX （第二行也是全满的）
& e# }+ p2 A! m. I' q1 R$ a, w9 i6 _4 W# R7 N
第三行：OX OX XO XOOX （第三行才出现洞）9 b- O5 M& J4 i2 ^; E: F8 u3 T, o
4 a5 p) Z% @4 ~, ]
第四行：O XO O XXX , N9 r, G4 ]/ ~. K. e! {
, s% F& ^2 j' m9 k 第五行： O
/ w, g$ O3 x4 M1 ]* y2 l- g8 k' @
$ q# S7 R( S) @! k9 C 通过以上排列，大家看见了，变换了组合方式以后，大路不再显的那么杂乱无章了。每一列要么是连，要么就是跳连。这就似乎是最初期的关系形态变化组合排列，通过这样的排列，从形态上看，整个路只有12个形态上的跳，其他全是连贯的（可能已经有人开窍了）。: d$ c' g- ~# |# E, P, S7 E1 h
6 J; E. `- @0 y) c5 f/ Y
大家看第一行不再是完全的单跳，第二行没有洞的出现，第三行才开始出现洞，每一列最少是2个符号，通过这样的形态组合，实际上是减少了原本大路上的跳40%-60%，比如原来一靴牌60把，基本上是30个跳。30个左右连，而且是间隔无规律，杂乱无章的，按常规跳连的次数是基本一致的，周期越大，数字越接近。1 D- p! i0 J v; \& a, M3 I) S
?' \1 ?0 }, T. _ B9 ^ 通过配列 可以把原本大路的跳精简到10-15个左右，相反增加了40-60%的连，以上是对大路形态转换的最初级形态，相信已经能对大家有帮助。至于怎么样去下单 ，一目了然了。
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