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3 D$ _% C5 o) ~2 K* }6 {/ G$ r! d3 ?5 B7 Q% ~9 u+ A+ A
通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
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假设大路开这样的路:
Z) v' n4 T4 C# o+ Y, E$ L; a! V- Y( g" V% g$ e2 \
12121212121212121212121212121212。$ b4 H/ j+ T/ U1 Q! M
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按2珠路,就是BPBPBPBPBP。( }0 _' I( @3 S
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如果我们去掉第一口,就会出现完全相反的结果:9 |7 a9 I" P b7 W. m* b- ~
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21212121212121212121212121212121。; q# _0 M- I0 g" Y/ Y; h
# E3 h4 q6 s* a6 }1 I) f( H. Q2 y 变成了PBPBPBPBPB。2 N& P7 ?& ^6 [- ?2 T" v
% P# |' ]7 n5 {1 P% | 如果我们再去掉一口,又返回第一种情况了。! Q. |$ P3 P- D' H
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所以每一条大路,按2珠路排列,有2种不同的路数。9 z Z( m% g% J2 R0 }
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再举一个列子:
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% @ z2 B+ b3 q& \. F* f7 P 大路:122122122122122122。
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, o, j3 N+ c1 x 按三珠路排列:
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122,122,122,122,122,122。
7 f, n: {1 d; }; h F: V' I7 n! y2 |: n9 A! p: l9 `
去掉第一口,变成:7 \, r' k" X8 {" W" E( h t
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221,221,221,221,221,去掉前2口,变成:2 ^+ j8 _6 V! R3 Q: |. w. D! K4 O$ m
) X' ^ e* o$ d5 g 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。, f+ e0 M9 {3 O; c( D7 n
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同理:按N珠路排列,有N种不同的路数。
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我提出这个的意义在于:/ D8 s( ]* f/ |
2 w6 J& U+ W4 u1 W2 l, l 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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2、为三多理论提供了下注的多面性奠定基础。9 i! n; E' R3 @. J+ n: e
q6 [. s5 o$ ^# A7 s. N; x! \ 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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