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[打法交流] 百家乐蒙特卡洛战术
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          百家乐真的有很多战术,打法,发现了其中一种也是不错的,跟大家分享。那就是百家乐蒙特卡洛战术。只需要纸和笔做记录。但并不难。2 a. M( U  W; r; \3 y5 Q
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(1)首先写「123」的数列。
" f  x) {& w' q0 O1 s' S(2)赌本就是左端的数字(1)加右端的数字(3)即是(4)。
9 F$ x3 D& u4 `" A7 A" T# I(3)输了的话就在数列右端之外又加上顺序的下一个数,现在这个例子要加的数字(=4)->(「1234」)。如此类推,并且重复上面的第(2)点(但今次会是(1)+(4)=5)。
4 X# g" @2 Y/ Z$ {6 M(4)胜了的话,倍率2倍的游戏就把左端的数字(1)和右端的数字(3)消去。倍率3倍的游戏从数列上去掉左端的二个数字和右端的二个数字。( |9 y8 W! W# f  Z4 r7 I
(5)如果数列所有的数字都消了就代表结束。
+ q, l2 |* J8 Y6 Y4 o(6)想继续的话,回到(1)。+ O! C& N! b0 r) C, G

3 c4 O* t# n; Z) K( e          蒙特卡洛战术的问题在于,如果没有充足而源源不断的赌金,就有可能在途中被迫停止。如果连败,也有机会超越MaxBet(赌注的上限)。" O2 _: Z" z& H  b/ I/ P1 q" m. O
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          二合一战术。这可以说是蒙特卡洛战术的一种方是一局取回两局输掉的方法。方法简单。写下损失的金额,赌注左右数字的总金额。譬如,先写下「1」。所以第一局的赌注是1。如这局输了,右侧添写1,成为「11」。那个下一局赌注将会是左端和右端的共和=2。反复这样做,如四连败,数列将成为「1123」。因此下一赌注会是4,而且胜了的话,消去左端和右端的数字,数列将成「12」,下一赌注就等于1和2的总数3。再胜的话,会变成?尽管结果是2胜4败,但总收支是一加一减等于零。# w; w# E2 Y2 h/ T  }( }2 y9 }) W3 u  S
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完了,我的脑子真的不够用了,这个打法我看了两遍还是没搞明白
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这个也是要进来看看咯
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这个战术也是可以去学习下看看了啊
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主题回复处广告图案-天策传媒
听着就复杂,一直在研究了吧
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你这个战术 我一定是会好好学习   
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这个方法还是需要学习一下。
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对这个战术都一点也不了解的呀,没听说过
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这个战术是不是会有用的啊
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没有好的心态什么战术都是白答
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蒙特卡洛战术闻名不如见面啊
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面对百家乐最重要的战术,就是向他认输
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这也是一个非常的需要资本的战术
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这个战术以前好像在哪里见过
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:) :( :D :'( :@ :o
:P :$ ;P :L :Q :lol
:loveliness: :funk: :curse: :dizzy: :shutup: :sleepy:
:hug: :victory: :time: :kiss: :handshake: :call:
:) :( :D :'( :@ :o
:P :$ ;P :L :Q :lol
:loveliness: :funk: :curse: :dizzy: :shutup: :sleepy:
:hug: :victory: :time: :kiss: :handshake: :call:
:hug: :victory:
:) :( :D :'( :@ :o
:P :$ ;P :L :Q :lol
:loveliness: :funk: :curse: :dizzy: :shutup: :sleepy:
:hug: :victory: :time: :kiss: :handshake: :call:
:hug: :victory: :time: :kiss: :handshake: :call:
:hug: :victory: :time: :kiss: :handshake: :call:
:hug: :victory: :time: :kiss: :handshake: :call:
:hug: :victory: :time: :kiss: :handshake: :call:
:hug: :victory: :time: :kiss: :handshake:
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